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A comprehensive, mobile-friendly, SEO-optimized learning page for JSS 2 Mathematics second term. It covers every topic in the term, gives seven worked examples per topic, and includes a 40-question CBT quiz timed for 30 minutes with one question at a time navigation.
Second term mathematics in JSS 2 develops number skills, estimation, binary notation, open sentences, equations, and algebraic thinking. Each topic is presented with a lesson note, seven worked examples, and study support designed for classroom use and independent revision.
| Week | Topic | Core Content |
|---|---|---|
| 1 | Fractions Operations | Multiplication and division of fractions, simplification, word problems. |
| 2 | Approximation and Estimation | Rounding off numbers, estimating answers, accuracy and reasonable answers. |
| 3 | Binary Number System | Introduction to base two, conversion, and simple operations in binary. |
| 4 | Open Sentences and Equations | Symbols, open statements, simple equations, finding unknown values. |
| 5 | Algebraic Expressions | Terms, coefficients, like terms, simplification of expressions. |
| 6 | Revision and Class Assessment | Revision of all second-term topics and test preparation. |
In this topic, students learn how to multiply and divide fractions. The most important ideas are simplification, finding reciprocal fractions, and reducing answers to simplest form where possible.
Multiply the numerators together and multiply the denominators together.
Keep, change, and flip: keep the first fraction, change ÷ to ×, and flip the second fraction.
Simplify the answer fully when possible.
Question: 1/2 × 3/4 = 3/8.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: 2/3 × 6/5 = 12/15 = 4/5.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: 3/5 ÷ 2/7 = 3/5 × 7/2 = 21/10 = 2 1/10.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: 4/7 × 7/9 = 4/9 after cancelling 7.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: 5/6 ÷ 5/8 = 5/6 × 8/5 = 8/6 = 4/3 = 1 1/3.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: 2/9 × 3/4 = 6/36 = 1/6.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: 7/8 ÷ 7/16 = 7/8 × 16/7 = 16/8 = 2.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Approximation means writing a number close to the original number. Estimation means finding a quick and sensible answer. Both are useful for checking whether an answer is reasonable.
Use the place value to round to the nearest ten, hundred, thousand, or decimal place.
Replace numbers with easier values to get a quick answer.
Check if the exact answer is sensible.
Question: 47 rounded to the nearest ten is 50.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: 263 rounded to the nearest hundred is 300.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: 198 + 302 ≈ 200 + 300 = 500.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: 7,485 rounded to the nearest thousand is 7,000.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: 15.6 rounded to the nearest whole number is 16.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: 3,149 estimated to the nearest hundred is 3,100.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: 98 × 4 can be estimated as 100 × 4 = 400.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
The binary number system uses only two digits, 0 and 1. It is the base-2 number system and is very important in computers, digital devices, and electronic data processing.
Binary numbers are built with powers of 2.
Convert between base 10 and base 2 using repeated division or place value.
Computers use binary because they work with on/off states.
Question: 5 in binary is 101.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: 6 in binary is 110.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: 7 in binary is 111.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: 8 in binary is 1000.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: 10 in binary is 1010.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: 12 in binary is 1100.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: 13 in binary is 1101.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Open sentences contain unknown numbers. When the unknown is found, the sentence becomes true. Equations are useful for solving real-life problems in algebra and arithmetic.
Letters like x, y, n, or a stand for unknown values.
Use opposite operations to isolate the unknown.
Always substitute your answer to confirm it works.
Question: x + 5 = 12, so x = 7.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: 3n = 21, so n = 7.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: y - 4 = 9, so y = 13.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: 2x = 18, so x = 9.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: a / 5 = 6, so a = 30.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: m + 8 = 20, so m = 12.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: 4p = 32, so p = 8.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Algebraic expressions are combinations of numbers, letters, and operations without an equal sign. They are used to represent patterns and relationships and to prepare students for advanced algebra.
Only terms with the same variables and powers can be combined.
The number attached to a variable.
A mathematical phrase without an equal sign.
Question: 3x + 2x = 5x.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: 4a + 3b + 2a = 6a + 3b.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: 2y + 7y - 5y = 4y.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: 5m + 2m + m = 8m.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: 2(x + 5) = 2x + 10.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: 3(t - 4) = 3t - 12.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
Question: 7p - 2p + p = 6p.
Step 1: Identify the key values in the question.
Step 2: Apply the correct rule for the topic.
Step 3: State the final answer clearly and simplify if needed.
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40 questions | 30 minutes | One question at a time.
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