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Electrolysis — Comprehensive e-Book (JAMB / WAEC focus)
What you’ll learn — objectives & overview
Electrolysis is the process of using electrical energy to cause chemical change — driving non-spontaneous redox reactions by passing current through an electrolyte. It is central to metal extraction, refining, electroplating, and large-scale chemical production.
Key terms: electrolyte, electrode, anode (oxidation), cathode (reduction), ionic conduction.
Electrolytes dissociate into ions in solution or when molten and thus conduct electricity (e.g., NaCl, H₂SO₄, CuSO₄). Non-electrolytes (sugar, ethanol) do not dissociate and therefore don't conduct.
Ionic conduction occurs as cations migrate to the cathode and anions migrate to the anode under an applied electric field.
Useful constant: Faraday's constant F ≈ 96485 C per mole of electrons (C·mol⁻¹).
Given: 1.00×10⁵ C through Cu²⁺; equivalent weight (Cu) ≈ 31.75 g per equiv.
Mass = (Q / F) × equivalent weight = (1.00×10⁵ / 96485) × 31.75 ≈ 32.9 g.
Which species is discharged depends on reduction/oxidation potentials, concentration, and electrode material.
At cathode: Cu²⁺ + 2e⁻ → Cu(s). At inert anode: 2H₂O → O₂ + 4H⁺ + 4e⁻.
Primary factors: discharge potential (standard electrode potentials), ion concentration, electrode material, applied voltage and overpotential, temperature.
Example: In aqueous NaCl, H₂ is often evolved at cathode (water reduction) rather than Na⁺ because H₂O has a lower (less negative) reduction potential under aqueous conditions.
The electrochemical series ranks species by standard reduction potential. Cell potential E°cell = E°cathode − E°anode.
If E°(Cu²⁺/Cu)=+0.34 V and E°(Zn²⁺/Zn)=−0.76 V, E°cell = 0.34 − (−0.76) = 1.10 V.
Impure copper anode dissolves; Cu²⁺ migrates and is reduced at the cathode to give pure copper deposits.
Corrosion is an electrochemical (electrolytic) process. Protection methods include cathodic protection (sacrificial anode), coatings, electroplating, and impressed current systems.
A more reactive metal (e.g. zinc) is attached as sacrificial anode; it oxidizes instead of the protected metal.
Always balance electrons in half-reactions when doing Faraday calculations. Use F = 96485 C·mol⁻¹ and relate Q (Coulombs) to moles e⁻ then to moles of substance via stoichiometry.
Mass deposited = (Q / F) × (Moles e⁻ per mole product)⁻¹ × molar mass (or use equivalent weight directly).
When you click Start Quiz you'll enter a 30-question CBT with a 15-minute timer. Each question is shown one at a time. After submission you'll see a detailed breakdown with explanations.
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