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Is your relationship worth repairing? Get "Build Before You Promise" → Relationship Repair When Love Is Still There but the Relationship Is Falling Apart Sometimes the relationship does not need another argument. It needs two people willing to stop defending themselves long enough to understand what is actually breaking. By Edwin Ogie • Author of The Relationship Repair Handbook , Build Before You Promise , Emotional Mastery , and The Value of You Not every broken relationship is a relationship without love. Sometimes two people still love each other deeply, but they have become exhausted by unresolved arguments, poor communication, resentment, disappointment and repeated misunderstandings. They may still care. They may still want the relationship. They may e...

Quadratic equations

Quadratic Equations

Quadratic Equations

A quadratic equation is a second-degree polynomial equation in one variable, typically written in the standard form:

ax² + bx + c = 0

where:

  • a, b, and c are constants.
  • a ≠ 0 (if a = 0, the equation becomes linear).

Key Features of a Quadratic Equation

  1. Degree: The highest power of x is 2.
  2. Roots: The solutions of the quadratic equation are called roots. These are the values of x that satisfy ax² + bx + c = 0.
  3. Discriminant (D): Determines the nature of roots and is given by:
    D = b² - 4ac
    • If D > 0: Two distinct real roots.
    • If D = 0: Two equal real roots (repeated roots).
    • If D < 0: No real roots (complex roots).

Methods of Solving Quadratic Equations

  • Factorization
  • Completing the Square
  • Using the Quadratic Formula:
    x = (-b ± √(b² - 4ac)) / 2a
  • Graphing (to visualize roots)

Example Problems

1. Solving by Factorization

Solve x² - 5x + 6 = 0.

x² - 5x + 6 = 0
x² - 2x - 3x + 6 = 0
x(x - 2) - 3(x - 2) = 0
(x - 2)(x - 3) = 0
x = 2 or x = 3
    

2. Solving by Completing the Square

Solve x² + 6x + 5 = 0.

x² + 6x + 5 = 0
x² + 6x = -5
x² + 6x + 9 = 4
(x + 3)² = 4
x + 3 = ±2
x = -1 or x = -5
    

3. Solving by Using the Quadratic Formula

Solve 2x² - 4x - 6 = 0.

x = (-b ± √(b² - 4ac)) / 2a
x = (4 ± √(16 + 48)) / 4
x = (4 ± √64) / 4
x = (4 ± 8) / 4
x = 3 or x = -1
    

4. Solving When D < 0

Solve x² + 4x + 5 = 0.

D = b² - 4ac = 4² - 4(1)(5) = -4
x = (-4 ± √-4) / 2
x = -2 ± i
x = -2 + i or x = -2 - i
    

5. Word Problem Involving Quadratic Equations

The product of two consecutive integers is 56. Find the integers.

Let the integers be x and x + 1.
x(x + 1) = 56
x² + x - 56 = 0
(x + 8)(x - 7) = 0
x = -8 or x = 7
The integers are -8 and -7 or 7 and 8.
    

Applications of Quadratic Equations

  • Physics (projectile motion, acceleration)
  • Finance (profit maximization, breaking even)
  • Geometry (finding dimensions, areas)
  • Engineering (design and analysis)

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