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3-Phase Servo AVR (AC Voltage Stabilizer) — Parts, Tests, Repair & Maintenance

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3-Phase Servo AVR (AC Voltage Stabilizer) — Troubleshooting, Repair & Maintenance By Edwin Ogie • December 18, 2025 • -- AC Voltage Stabilizer — 3-phase servo control type (example from user photo) A practical, step-by-step guide to diagnose, repair and maintain 3-phase servo Automatic Voltage Regulators (AVR) / servo voltage stabilizers. Written in simple terms for technicians and maintenance teams working with generators, UPS rooms and factories. Includes videos, spare-parts list, safety checklist, troubleshooting flow and links to internal/external resources. Contents Why this matters In environments with unstable mains (frequent sags, surges or phase imbalance) a servo AVR protects sensitive equipment by continuously adjusting an autotransformer tap via a small servo motor. A well-maintained stabilizer saves equipment, reduces downtime and prevents costly damage. ...

Quadratic equations

Quadratic Equations

Quadratic Equations

A quadratic equation is a second-degree polynomial equation in one variable, typically written in the standard form:

ax² + bx + c = 0

where:

  • a, b, and c are constants.
  • a ≠ 0 (if a = 0, the equation becomes linear).

Key Features of a Quadratic Equation

  1. Degree: The highest power of x is 2.
  2. Roots: The solutions of the quadratic equation are called roots. These are the values of x that satisfy ax² + bx + c = 0.
  3. Discriminant (D): Determines the nature of roots and is given by:
    D = b² - 4ac
    • If D > 0: Two distinct real roots.
    • If D = 0: Two equal real roots (repeated roots).
    • If D < 0: No real roots (complex roots).

Methods of Solving Quadratic Equations

  • Factorization
  • Completing the Square
  • Using the Quadratic Formula:
    x = (-b ± √(b² - 4ac)) / 2a
  • Graphing (to visualize roots)

Example Problems

1. Solving by Factorization

Solve x² - 5x + 6 = 0.

x² - 5x + 6 = 0
x² - 2x - 3x + 6 = 0
x(x - 2) - 3(x - 2) = 0
(x - 2)(x - 3) = 0
x = 2 or x = 3
    

2. Solving by Completing the Square

Solve x² + 6x + 5 = 0.

x² + 6x + 5 = 0
x² + 6x = -5
x² + 6x + 9 = 4
(x + 3)² = 4
x + 3 = ±2
x = -1 or x = -5
    

3. Solving by Using the Quadratic Formula

Solve 2x² - 4x - 6 = 0.

x = (-b ± √(b² - 4ac)) / 2a
x = (4 ± √(16 + 48)) / 4
x = (4 ± √64) / 4
x = (4 ± 8) / 4
x = 3 or x = -1
    

4. Solving When D < 0

Solve x² + 4x + 5 = 0.

D = b² - 4ac = 4² - 4(1)(5) = -4
x = (-4 ± √-4) / 2
x = -2 ± i
x = -2 + i or x = -2 - i
    

5. Word Problem Involving Quadratic Equations

The product of two consecutive integers is 56. Find the integers.

Let the integers be x and x + 1.
x(x + 1) = 56
x² + x - 56 = 0
(x + 8)(x - 7) = 0
x = -8 or x = 7
The integers are -8 and -7 or 7 and 8.
    

Applications of Quadratic Equations

  • Physics (projectile motion, acceleration)
  • Finance (profit maximization, breaking even)
  • Geometry (finding dimensions, areas)
  • Engineering (design and analysis)

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