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3-Phase Servo AVR (AC Voltage Stabilizer) — Parts, Tests, Repair & Maintenance

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3-Phase Servo AVR (AC Voltage Stabilizer) — Troubleshooting, Repair & Maintenance By Edwin Ogie • December 18, 2025 • -- AC Voltage Stabilizer — 3-phase servo control type (example from user photo) A practical, step-by-step guide to diagnose, repair and maintain 3-phase servo Automatic Voltage Regulators (AVR) / servo voltage stabilizers. Written in simple terms for technicians and maintenance teams working with generators, UPS rooms and factories. Includes videos, spare-parts list, safety checklist, troubleshooting flow and links to internal/external resources. Contents Why this matters In environments with unstable mains (frequent sags, surges or phase imbalance) a servo AVR protects sensitive equipment by continuously adjusting an autotransformer tap via a small servo motor. A well-maintained stabilizer saves equipment, reduces downtime and prevents costly damage. ...

Dynamics 2

Dynamics: Equations of Motion

Dynamics: Equations of Motion

Learn the fundamentals of motion with derivations and worked examples

Derivation of Equations of Motion

The three primary equations of motion relate the displacement, velocity, acceleration, and time of a moving object. They are derived using the assumption of uniform acceleration:

1. First Equation of Motion: v = u + at

From the definition of acceleration:

Acceleration (a) = Change in Velocity / Time a = (v - u) / t Rearranging gives: v = u + at

2. Second Equation of Motion: s = ut + (1/2)at²

Using the definition of average velocity:

Average Velocity = (Initial Velocity + Final Velocity) / 2 v_avg = (u + v) / 2 Displacement (s) = Average Velocity × Time s = [(u + v) / 2] × t

Substitute v = u + at from the first equation:

s = [u + (u + at)] × t / 2 s = ut + (1/2)at²

3. Third Equation of Motion: v² = u² + 2as

Starting from the first equation:

v = u + at Multiply through by v + u: v² - u² = 2as Rearrange to: v² = u² + 2as

Worked Examples

Example 1

Problem: A car travels a distance of 120 m in 15 seconds. Calculate the speed of the car.

Solution:

Using Speed = Distance / Time:

Speed = 120 / 15 = 8 m/s

Example 2

Problem: A cyclist starts from rest and accelerates uniformly at 2 m/s². Find the velocity after 10 seconds.

Solution:

Using v = u + at:

v = 0 + (2 × 10) = 20 m/s

Example 3

Problem: A ball is dropped from a height of 45 m. How long does it take to hit the ground? (Take g = 10 m/s²)

Solution:

Using s = ut + 1/2gt²:

45 = 0 + (1/2)(10)t² 45 = 5t² t² = 9 t = 3 s

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