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This e‑book covers:
1. Representation of Data: frequency distribution; histogram, bar chart, and pie chart.
2. Measures of Location: mean, mode, and median (ungrouped and grouped data) and cumulative frequency (using ogives).
3. Measures of Dispersion: range, mean deviation, variance, and standard deviation.
Statistics is the science of collecting, analyzing, presenting, and interpreting data. It plays a crucial role in many fields by enabling us to summarize and make sense of large amounts of information.
This e‑book focuses on the representation of data, measures of location, and measures of dispersion. We also learn how to use an ogive to find the median, quartiles, and percentiles.
A frequency distribution is a table that shows the number of times (frequency) that each value or range of values occurs in a data set.
Example Table:
| Class Interval | Frequency |
|---|---|
| 0 - 9 | 5 |
| 10 - 19 | 8 |
| 20 - 29 | 12 |
| 30 - 39 | 7 |
Frequency distribution tables help us to organize and interpret data easily.
Data can be represented graphically in various forms:
Each graphical method provides a visual summary of the data.
Measures of location describe the central tendency of a data set. They include:
For grouped data, these measures are calculated using class midpoints and frequencies.
Cumulative Frequency: A running total of frequencies, useful for drawing an ogive to determine the median, quartiles, and percentiles.
Measures of dispersion show how spread out the data are. They include:
An ogive is a graph of the cumulative frequency distribution. It helps in finding the median, quartiles, and percentiles.
Example: Plot the cumulative frequency against the upper class boundaries to determine the median (50th percentile) and quartiles.
Mastery of these statistical tools is essential for data analysis and decision-making.
Statistics is widely used in various fields, including business, economics, health, and social sciences. Understanding data representation, central tendency, and dispersion allows analysts to interpret trends and make informed decisions.
Applications include designing surveys, quality control in manufacturing, and public policy planning.
Question: Given the data: 12, 15, 12, 18, 20, 15, 15, 18, create a frequency distribution table.
Solution:
| Value | Frequency |
|---|---|
| 12 | 2 |
| 15 | 3 |
| 18 | 2 |
| 20 | 1 |
Question: From the frequency table in Example 1, what is the mode of the data?
Solution:
The mode is the value with the highest frequency. Here, 15 appears 3 times, so the mode is 15.
Question: Describe how you would construct a histogram from the frequency table in Example 1.
Solution:
Plot the values on the horizontal axis and frequency on the vertical axis. Draw bars for each value with heights corresponding to their frequencies.
Question: Explain how a bar chart differs from a histogram using the frequency distribution from Example 1.
Solution:
A bar chart uses separate bars with gaps in between to represent categorical data. Although similar to a histogram, a bar chart is typically used for discrete categories rather than continuous intervals.
Question: How would you represent the data from Example 1 in a pie chart?
Solution:
Calculate the percentage for each value (e.g., for 15: (3/8)*100 ≈ 37.5%). Draw a circle and divide it into sectors proportional to these percentages.
Question: Given the data: 5, 7, 8, 10, calculate the mean.
Solution:
Mean = (5+7+8+10) / 4 = 30 / 4 = 7.5.
Question: Find the median of the data: 4, 8, 6, 10, 12.
Solution:
Order the data: 4, 6, 8, 10, 12. The median is the middle value: 8.
Question: Using the following grouped data, calculate the mean:
Class Interval
Frequency
0 - 9
4
10 - 19
6
20 - 29
5
Solution:
Calculate midpoints: 4.5, 14.5, 24.5.
Total frequency = 4+6+5 = 15.
Mean = (4×4.5 + 6×14.5 + 5×24.5) / 15 = (18 + 87 + 122.5) / 15 = 227.5/15 ≈ 15.17.
Question: Given the cumulative frequency table below, determine the median class interval.
Class Interval
Cumulative Frequency
0 - 9
5
10 - 19
12
20 - 29
20
Solution:
Total frequency = 20. Median is at the 10th value. The 10th value falls in the 10 - 19 interval.
Question: Given the data: 3, 7, 8, 12, 15, calculate the range.
Solution:
Range = Maximum - Minimum = 15 - 3 = 12.
Question: For the data set: 4, 6, 8, calculate the mean deviation from the mean.
Solution:
Mean = (4+6+8)/3 = 6.
Deviations: |4-6|=2, |6-6|=0, |8-6|=2.
Mean deviation = (2+0+2)/3 ≈ 1.33.
Question: Find the variance of the data: 2, 4, 6.
Solution:
Mean = (2+4+6)/3 = 4.
Squared deviations: (2-4)²=4, (4-4)²=0, (6-4)²=4.
Variance = (4+0+4)/3 = 8/3 ≈ 2.67.
Question: Calculate the standard deviation of the data: 3, 7, 11.
Solution:
Mean = (3+7+11)/3 = 7.
Variance = [(3-7)² + (7-7)² + (11-7)²] / 3 = (16+0+16)/3 = 32/3 ≈ 10.67.
Standard deviation = √(10.67) ≈ 3.27.
Question: Explain how an ogive is used to determine the first quartile (Q1) of a data set.
Solution:
Plot the cumulative frequency against the upper boundaries of the class intervals. The first quartile (Q1) is the value corresponding to 25% of the total frequency on the ogive.
Question: Describe how you would find the 90th percentile of a data set using an ogive.
Solution:
Determine 90% of the total frequency, then locate this value on the cumulative frequency axis. Read the corresponding value on the horizontal axis of the ogive; this value is the 90th percentile.
Click the "Start Quiz" button to begin. You will have 15 minutes to answer 30 questions.
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