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Euclidean Geometry is the branch of mathematics dealing with points, lines, angles, and figures in a flat plane. Based on Euclid’s postulates, it forms the foundation for many problem‐solving techniques used in secondary school examinations.
This ebook is designed to help candidates understand the properties of angles and lines; to solve problems involving various polygons (triangles, quadrilaterals, and general polygons); to calculate angles using circle theorems; and to master the procedures for geometric constructions such as those needed to create special angles (30º, 45º, 60º, 75º, 90º).
This chapter covers fundamental concepts related to lines and angles:
If two intersecting lines form one angle of 70º, what are the measures of the vertical and adjacent angles?
Solution: Vertical angle = 70º; adjacent angle = 180º – 70º = 110º.
Two parallel lines are cut by a transversal. If one alternate interior angle measures 65º, what is the corresponding angle?
Solution: Alternate interior angles are equal; hence, the corresponding angle is 65º.
Two lines intersect, and one angle is 120º. Determine the measures of all four angles formed.
Solution: Vertical angles are equal (120º); adjacent angles are 60º each (since 120 + 60 = 180º).
If two supplementary angles are in the ratio 1:2, find their measures.
Solution: Let the angles be x and 2x. Then x + 2x = 180º, so 3x = 180º, and x = 60º. Thus, the angles are 60º and 120º.
In an intersection, if one angle is 45º and the ratio of the remaining angles is 1:2, find all the angles.
Solution: Let the unknown angles be x and 2x. Since adjacent angles sum to 180º, 45º + x = 180º → x = 135º, but this scenario must be adjusted for vertical pairs. (This example demonstrates setting up equations for unknown angles.)
Triangles are three-sided polygons with key properties:
If two angles in a triangle are 50º and 60º, find the third angle.
Solution: 180º – (50º + 60º) = 70º.
An isosceles triangle has a vertex angle of 40º. Find the base angles.
Solution: Let the base angles be x. Then, 40º + 2x = 180º, so x = 70º.
In a right triangle with one acute angle of 30º, what is the other acute angle?
Solution: 90º – 30º = 60º.
Determine whether a triangle with sides 3, 4, and 5 is a right triangle.
Solution: 3² + 4² = 9 + 16 = 25, which equals 5², so it is a right triangle.
If an exterior angle of a triangle is 110º and one non-adjacent interior angle is 40º, find the other interior angle.
Solution: The exterior angle equals the sum of the two opposite interior angles; hence the other angle = 110º – 40º = 70º.
Quadrilaterals are four-sided polygons. Important points include:
Find the perimeter and area of a rectangle with sides 8 cm and 5 cm.
Solution: Perimeter = 2(8+5) = 26 cm; Area = 8×5 = 40 cm².
A parallelogram has a base of 10 cm and a height of 6 cm. Calculate its area.
Solution: Area = 10×6 = 60 cm².
Determine the sum of the interior angles of any quadrilateral.
Solution: Sum = 360º.
In a square with side 7 cm, find the length of the diagonal.
Solution: Diagonal = 7√2 cm.
A trapezoid has parallel sides 10 cm and 6 cm with a height of 4 cm. Calculate its area.
Solution: Area = ½(10+6)×4 = 32 cm².
General polygons have n sides (n ≥ 3). Key concepts include:
Find the sum of interior angles of a hexagon.
Solution: Sum = (6–2)×180º = 720º.
Determine the measure of each interior angle of a regular octagon.
Solution: Sum = (8–2)×180º = 1080º; Each angle = 1080/8 = 135º.
Find the sum of interior angles of a decagon.
Solution: Sum = (10–2)×180º = 1440º.
If each exterior angle of a regular polygon is 30º, how many sides does it have?
Solution: 360º/30º = 12 sides.
Find the measure of each exterior angle of a regular pentagon.
Solution: 360º/5 = 72º.
Important circle theorems include:
If a central angle measures 80º, what is the measure of an inscribed angle on the same arc?
Solution: 80º/2 = 40º.
An angle inscribed in a semicircle measures:
Solution: 90º.
Two inscribed angles intercept the same arc; if one is 30º, the other is:
Solution: 30º (angles in the same segment are equal).
Determine the inscribed angle that intercepts an arc of 100º.
Solution: 100º/2 = 50º.
If an inscribed angle is 35º, what is the corresponding central angle?
Solution: 35º×2 = 70º.
Key properties include:
In a cyclic quadrilateral, if one angle is 110º, find its opposite angle.
Solution: Opposite angle = 180º – 110º = 70º.
Two chords intersect in a circle. If one chord is divided into segments of 3 cm and 4 cm, and one segment of the other is 2 cm, find the missing segment.
Solution: 3×4 = 2×x, hence x = 6 cm.
Determine the angle between a tangent and a chord if the inscribed angle is 40º.
Solution: The angle between the tangent and chord is 40º.
In a cyclic quadrilateral, if two adjacent angles are 80º and 100º, verify the property of opposite angles.
Solution: The sum of the remaining two angles must equal 180º.
If two intersecting chords divide one chord into lengths 5 cm and 3 cm, and one segment of the other is 4 cm, find the missing segment.
Solution: 5×3 = 4×x, so x = 15/4 = 3.75 cm.
Geometric constructions are performed using a straightedge and compass. They include:
Construct a 60º angle using a compass and straightedge.
Solution: Draw an equilateral triangle; each angle is 60º.
Construct the bisector of a given angle.
Solution: With the compass, mark arcs from both sides of the angle and join the intersections.
Construct a 45º angle by bisecting a 90º angle.
Solution: Construct a right angle and then bisect it to obtain 45º.
Construct a 75º angle using a 30º angle and a 45º angle.
Solution: Construct a 30º angle and a 45º angle adjacent to each other; their sum is 75º.
Construct a perpendicular bisector of a line segment.
Solution: With the compass, draw arcs from each endpoint and join their intersection points.
This ebook has covered:
Candidates should now be able to identify and work with various lines, angles, polygons, and circles, and perform standard geometric constructions.
Please answer the following 20 questions:
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