3-Phase Servo AVR (AC Voltage Stabilizer) — Parts, Tests, Repair & Maintenance
Edwin Ogie Library is a dynamic platform for education, focused on fostering mindful communication and building positive relationships by eliminating linguistic errors. Our mission is to enhance connections through thoughtful language, emotional regulation, and self-awareness, providing educational resources that inspire personal growth. We aim to promote well-being, peace, and meaningful connections, offering a space for individuals committed to refining their communication skills.
Edwin Ogie Library - A Comprehensive Guide
Projectile motion refers to the motion of an object that is projected into the air and is subjected only to the force of gravity and air resistance (though air resistance is often neglected in basic physics calculations). The path that the object follows is called its trajectory, and it is influenced by the object's initial velocity, the angle of launch, and the force of gravity.
In projectile motion, there are several key variables that determine the motion of the projectile:
The total time of flight for a projectile is given by:
Formula: T = (2 * u * sin(θ)) / g
Where:
u = initial velocity, θ = launch angle, g = acceleration due to gravity (approximately 9.8 m/s²).
The maximum height reached by a projectile is given by:
Formula: H = (u² * sin²(θ)) / (2 * g)
Where:
u = initial velocity, θ = launch angle, g = acceleration due to gravity.
The range or horizontal distance traveled by the projectile is given by:
Formula: R = (u² * sin(2θ)) / g
Where:
u = initial velocity, θ = launch angle, g = acceleration due to gravity.
A ball is thrown with an initial velocity of 20 m/s at an angle of 30°. Calculate the time of flight.
Solution:
u = 20 m/s, θ = 30°, g = 9.8 m/s²
Using the formula: T = (2 * 20 * sin(30°)) / 9.8
Answer: T = 4.08 seconds
Given the same projectile, calculate the maximum height reached.
Solution:
H = (20² * sin²(30°)) / (2 * 9.8)
Answer: H = 5.1 meters
Given the same initial conditions, calculate the range.
Solution:
R = (20² * sin(60°)) / 9.8
Answer: R = 35.7 meters
If a projectile is launched at an angle of 45° and covers a range of 100 meters, calculate the initial velocity.
Solution:
R = (u² * sin(90°)) / 9.8
100 = (u²) / 9.8
u = 28.3 m/s
Answer: u = 28.3 m/s
Determine the launch angle needed for a projectile to achieve a maximum range with a velocity of 30 m/s.
Solution:
To maximize range, the angle should be 45°.
Comments
Post a Comment
We’d love to hear from you! Share your thoughts or questions below. Please keep comments positive and meaningful, Comments are welcome — we moderate for spam and civility; please be respectful.