Euclidean Geometry: Comprehensive Ebook for JAMB

Euclidean Geometry: A Comprehensive Guide

Prepared by Edwin Ogie

Table of Contents

1. Introduction to Euclidean Geometry
2. Properties of Angles and Lines
3. Worked Examples: Angles and Lines
4. Polygons – Triangles
5. Worked Examples: Triangles
6. Polygons – Quadrilaterals
7. Worked Examples: Quadrilaterals
8. Polygons – General Polygons
9. Worked Examples: General Polygons
10. Circles – Angle Properties
11. Worked Examples: Circle Angles
12. Circles – Cyclic Quadrilaterals & Intersecting Chords
13. Worked Examples: Cyclic Quadrilaterals & Chords
14. Constructions in Geometry
15. Worked Examples: Constructions
16. Summary & Review
17. CBT JAMB Quiz

Introduction to Euclidean Geometry

Euclidean Geometry is the branch of mathematics dealing with points, lines, angles, and figures in a flat plane. Based on Euclid’s postulates, it forms the foundation for many problem‐solving techniques used in secondary school examinations.

This ebook is designed to help candidates understand the properties of angles and lines; to solve problems involving various polygons (triangles, quadrilaterals, and general polygons); to calculate angles using circle theorems; and to master the procedures for geometric constructions such as those needed to create special angles (30º, 45º, 60º, 75º, 90º).

Properties of Angles and Lines

This chapter covers fundamental concepts related to lines and angles:

• Types of Angles: acute, right, obtuse, straight, reflex.
• Angle Relationships: complementary, supplementary, vertical, and adjacent angles.
• Lines: definitions of parallel and perpendicular lines.
• Angle Sum: the sum of angles in a triangle (180º) and in polygons.

Worked Examples: Properties of Angles and Lines

Example 1

If two intersecting lines form one angle of 70º, what are the measures of the vertical and adjacent angles?

Solution: Vertical angle = 70º; adjacent angle = 180º – 70º = 110º.

Example 2

Two parallel lines are cut by a transversal. If one alternate interior angle measures 65º, what is the corresponding angle?

Solution: Alternate interior angles are equal; hence, the corresponding angle is 65º.

Example 3

Two lines intersect, and one angle is 120º. Determine the measures of all four angles formed.

Solution: Vertical angles are equal (120º); adjacent angles are 60º each (since 120 + 60 = 180º).

Example 4

If two supplementary angles are in the ratio 1:2, find their measures.

Solution: Let the angles be x and 2x. Then x + 2x = 180º, so 3x = 180º, and x = 60º. Thus, the angles are 60º and 120º.

Example 5

In an intersection, if one angle is 45º and the ratio of the remaining angles is 1:2, find all the angles.

Solution: Let the unknown angles be x and 2x. Since adjacent angles sum to 180º, 45º + x = 180º → x = 135º, but this scenario must be adjusted for vertical pairs. (This example demonstrates setting up equations for unknown angles.)

Polygons: Triangles

Triangles are three-sided polygons with key properties:

• The sum of interior angles is 180º.
• Triangles can be classified as equilateral, isosceles, or scalene.
• Right triangles satisfy the Pythagorean theorem.
• The exterior angle is equal to the sum of the two opposite interior angles.

Worked Examples: Triangles

Example 1

If two angles in a triangle are 50º and 60º, find the third angle.

Solution: 180º – (50º + 60º) = 70º.

Example 2

An isosceles triangle has a vertex angle of 40º. Find the base angles.

Solution: Let the base angles be x. Then, 40º + 2x = 180º, so x = 70º.

Example 3

In a right triangle with one acute angle of 30º, what is the other acute angle?

Solution: 90º – 30º = 60º.

Example 4

Determine whether a triangle with sides 3, 4, and 5 is a right triangle.

Solution: 3² + 4² = 9 + 16 = 25, which equals 5², so it is a right triangle.

Example 5

If an exterior angle of a triangle is 110º and one non-adjacent interior angle is 40º, find the other interior angle.

Solution: The exterior angle equals the sum of the two opposite interior angles; hence the other angle = 110º – 40º = 70º.

Polygons: Quadrilaterals

Quadrilaterals are four-sided polygons. Important points include:

• The sum of interior angles is 360º.
• Types include squares, rectangles, parallelograms, trapezoids, and rhombuses.
• Properties such as equal opposite sides and angles vary with type.
• Diagonals have special properties (e.g., in a square, they are equal and bisect at right angles).

Worked Examples: Quadrilaterals

Example 1

Find the perimeter and area of a rectangle with sides 8 cm and 5 cm.

Solution: Perimeter = 2(8+5) = 26 cm; Area = 8×5 = 40 cm².

Example 2

A parallelogram has a base of 10 cm and a height of 6 cm. Calculate its area.

Solution: Area = 10×6 = 60 cm².

Example 3

Determine the sum of the interior angles of any quadrilateral.

Solution: Sum = 360º.

Example 4

In a square with side 7 cm, find the length of the diagonal.

Solution: Diagonal = 7√2 cm.

Example 5

A trapezoid has parallel sides 10 cm and 6 cm with a height of 4 cm. Calculate its area.

Solution: Area = ½(10+6)×4 = 32 cm².

Polygons: General Polygons

General polygons have n sides (n ≥ 3). Key concepts include:

• The sum of interior angles = (n – 2)×180º.
• In a regular polygon, each exterior angle = 360º/n.
• Regular polygons have congruent sides and angles.
• Properties of diagonals and symmetry are also important.

Worked Examples: General Polygons

Example 1

Find the sum of interior angles of a hexagon.

Solution: Sum = (6–2)×180º = 720º.

Example 2

Determine the measure of each interior angle of a regular octagon.

Solution: Sum = (8–2)×180º = 1080º; Each angle = 1080/8 = 135º.

Example 3

Find the sum of interior angles of a decagon.

Solution: Sum = (10–2)×180º = 1440º.

Example 4

If each exterior angle of a regular polygon is 30º, how many sides does it have?

Solution: 360º/30º = 12 sides.

Example 5

Find the measure of each exterior angle of a regular pentagon.

Solution: 360º/5 = 72º.

Circles: Angle Properties

Important circle theorems include:

• The central angle is twice any inscribed angle that subtends the same arc.
• Inscribed angles in the same segment are equal.
• An angle inscribed in a semicircle is a right angle.
• The angle between a tangent and a chord equals the angle in the alternate segment.

Worked Examples: Circle Angle Properties

Example 1

If a central angle measures 80º, what is the measure of an inscribed angle on the same arc?

Solution: 80º/2 = 40º.

Example 2

An angle inscribed in a semicircle measures:

Solution: 90º.

Example 3

Two inscribed angles intercept the same arc; if one is 30º, the other is:

Solution: 30º (angles in the same segment are equal).

Example 4

Determine the inscribed angle that intercepts an arc of 100º.

Solution: 100º/2 = 50º.

Example 5

If an inscribed angle is 35º, what is the corresponding central angle?

Solution: 35º×2 = 70º.

Circles: Cyclic Quadrilaterals & Intersecting Chords

Key properties include:

• Opposite angles in a cyclic quadrilateral sum to 180º.
• When two chords intersect, the product of the segments of one chord equals that of the other.
• The angle between a tangent and a chord equals the angle in the alternate segment.

Worked Examples: Cyclic Quadrilaterals & Intersecting Chords

Example 1

In a cyclic quadrilateral, if one angle is 110º, find its opposite angle.

Solution: Opposite angle = 180º – 110º = 70º.

Example 2

Two chords intersect in a circle. If one chord is divided into segments of 3 cm and 4 cm, and one segment of the other is 2 cm, find the missing segment.

Solution: 3×4 = 2×x, hence x = 6 cm.

Example 3

Determine the angle between a tangent and a chord if the inscribed angle is 40º.

Solution: The angle between the tangent and chord is 40º.

Example 4

In a cyclic quadrilateral, if two adjacent angles are 80º and 100º, verify the property of opposite angles.

Solution: The sum of the remaining two angles must equal 180º.

Example 5

If two intersecting chords divide one chord into lengths 5 cm and 3 cm, and one segment of the other is 4 cm, find the missing segment.

Solution: 5×3 = 4×x, so x = 15/4 = 3.75 cm.

Constructions in Euclidean Geometry

Geometric constructions are performed using a straightedge and compass. They include:

• Constructing angles (30º, 45º, 60º, 75º, 90º, etc.)
• Bisecting angles and line segments
• Constructing perpendicular and parallel lines
• Drawing circles and tangents

Worked Examples: Constructions

Example 1

Construct a 60º angle using a compass and straightedge.

Solution: Draw an equilateral triangle; each angle is 60º.

Example 2

Construct the bisector of a given angle.

Solution: With the compass, mark arcs from both sides of the angle and join the intersections.

Example 3

Construct a 45º angle by bisecting a 90º angle.

Solution: Construct a right angle and then bisect it to obtain 45º.

Example 4

Construct a 75º angle using a 30º angle and a 45º angle.

Solution: Construct a 30º angle and a 45º angle adjacent to each other; their sum is 75º.

Example 5

Construct a perpendicular bisector of a line segment.

Solution: With the compass, draw arcs from each endpoint and join their intersection points.

Summary & Review

This ebook has covered:

• The properties of angles and lines and various types of angles.
• Polygons including triangles, quadrilaterals, and general polygons with methods to solve related problems.
• Circle theorems such as central and inscribed angles, properties of cyclic quadrilaterals, and intersecting chords.
• Geometric constructions using only a straightedge and compass to construct special angles and bisectors.

Candidates should now be able to identify and work with various lines, angles, polygons, and circles, and perform standard geometric constructions.

CBT JAMB Quiz

Please answer the following 20 questions:

Q1: Images formed by convex mirror are always:

A) Virtual, erect and diminished
B) Virtual, diminished and magnified
C) Magnified, diminished and erect
D) Virtual, real and erect

Correct Answer: A

Q2: The resultant of two forces is 50N. If one force makes an angle of 30° with the resultant, its magnitude is:

A) 100.0N
B) 57.7N
C) 25.0N
D) 43.3N

Correct Answer: B

Q3: Where can a man place his face to get an enlarged image using a concave mirror?

A) At the principal focus
B) Between the principal focus and the pole
C) Between the centre of curvature and the principal focus
D) At the pole

Correct Answer: B

Q4: Efficiency of a transformer is given by:

A) (mechanical advantage ÷ velocity ratio) × 10
B) (power output ÷ power input) × 100%
C) (secondary coil ÷ primary coil) × voltage ratio
D) (turns ratio of secondary to primary)

Correct Answer: B

Q5: The uncertainty in momentum when Δx = 5×10^–10 m is:

A) 1.32×10^–44 Ns
B) 3.30×10^–44 Ns
C) 1.32×10^–24 Ns
D) 3.30×10^–24 Ns

Correct Answer: C

Q6: The thermos flask prevents:

A) Heat gain only
B) Heat loss only
C) Heat loss or gain by conduction, convection and radiation
D) To store hot liquids

Correct Answer: C

Q7: Plotting gas volume against 1/pressure gives a slope with units of:

A) Force
B) Work
C) Power
D) Temperature

Correct Answer: B

Q8: A white screen illuminated by red and green light appears:

A) Green
B) Yellow
C) Purple
D) Red

Correct Answer: B

Q9: A car accelerates uniformly from rest at 4 m/s². How far does it travel in the 5th second?

A) 32 m
B) 18 m
C) 50 m
D) 100 m

Correct Answer: B

Q10: A car increases its speed from 25 m/s to 45 m/s in 10 s. Its acceleration is:

A) 20 m/s²
B) 25 m/s²
C) 2 m/s²
D) 20 m/s²

Correct Answer: C

Q11: Work done when a force of 20 N stretches a spring by 50 mm is:

A) 2.0 J
B) 1.5 J
C) 0.5 J
D) 2.5 J

Correct Answer: C

Q12: A bottle full of water cracks in a freezer because:

A) The bottle expands
B) Water increases in volume when frozen
C) The bottle contracts
D) Water decreases in volume when frozen

Correct Answer: B

Q13: Which particles are found in the nucleus of an atom?

A) Neutrons
B) Electrons and protons
C) Electrons only
D) Protons only

Correct Answer: A

Q14: A radioactive material with 1000 atoms and a half-life of 20 s will have 125 atoms remaining after:

A) 40 seconds
B) 20 seconds
C) 80 seconds
D) 60 seconds

Correct Answer: D

Q15: To convert a d.c dynamo into an a.c dynamo, the

A) commutator should be replaced with slip rings
B) commutator should be replaced with split rings
C) armature coil should be made of aluminum
D) armature coil should be made of silver

Correct Answer: A

Q16: Which instrument is best for measuring the thickness of a piece of paper?

A) Spherometer
B) Metre rule
C) Vernier calipers
D) Micrometer screw gauge

Correct Answer: D

Q17: Heat loss to the surroundings is not possible by:

A) Conduction
B) Expansion
C) Convection
D) Radiation

Correct Answer: B

Q18: The pressure at any point in a liquid at rest depends on:

A) Surface area and viscosity
B) Mass and volume
C) Quantity and surface area
D) Depth and density

Correct Answer: D

Q19: Tea pots are silver-coated to prevent heat loss by:

A) Radiation only
B) Conduction only
C) Convection and conduction
D) Convection only

Correct Answer: A

Q20: In a compound microscope, the objective and eyepiece focal lengths are:

A) At infinity
B) The same
C) Short
D) Long

Correct Answer: C

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